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Chapter 13 Control Sub Functions
Thus, AP, AL and AM
to be set are as follows.
AP = 2883584 ……[Pr.2] AP = 2883584 …[Pr.2]
AL = 67.50000 ….[Pr.3] or AL = 0.06750 …[Pr.3]
AM = 1 ………..….[Pr.4] AM = 1000 …….[Pr.4]
Note): These two examples of settings are only examples. There are
settings other than these examples.
(4) When "mm" is set as the control unit for conveyor drive
(calculation including
)
When the belt conveyor drive is used, the conveyor diameter is 135mm,
the pulley ratio is 1/3, the motor is HG-KR (4194304PLS/rev) and the
reduction ratio of the reduction gear is 7/53.
Reduction ratio 7/53
M
Pulley ratio 1/3
135mm
Belt
conveyor
As the travel value of the conveyor is used to exercise control, set "mm"
as the control unit.
First, find how many millimeters the load (machine) will travel (
S
) when
the motor turns one revolution (AP).
AP (Number of pulses per rotation) = 4194304 [PLS]
S
(Movement amount per rotation)
= 135000.0 [
m]
Reduction ratio
= 135000.0 [
m]
7/53
1/3
Substitute this for the above expression (1).
At this time, make calculation with the reduction ratio 7/53
1/3
remaining as a fraction.
AP
=
AP
=
4194304 [PLS]
S
AL
AM
135000.0 [
m]
7/53
1/3
=
4194304
53
3
135000.0
7
=
166723584
236250
Here, make calculation on the assumption that
is equal to
3.141592654.
AP
=
AP
=
166723584
S
AL
AM
742201.2645075