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Reference Manual
00809-0100-4860, Rev BC
Appendix C: Electronics verification
January 2013
Electronics verification
Example 2 (SI units)
Therefore, an input frequency of 650.00 Hz represents a flow rate of 3446.4 kg/hr in this
application.
For a given input frequency, you may also determine the current output. Use the prior example
with an input frequency of 275 Hz:
URV= 3600 kg/hr LRV= 0 kg/hr F
in
(Hz) = 275
= 10.48 mA
Therefore, an input frequency of 275.00 Hz represents an output current of 10.48 mA.
Fluid = Saturated Steam URV = 3600 kg/hr
Line size = 80 mm. LRV = 0 kg/hr
Line pressure = 700 kPas C
16
= C
11
/from Table
C-1 on page C-125
)
Operating
Temperature
= 170 °F Density() = 4.169 kg/cu-mtr
(operating)
Viscosity = 0.015 cp
Input
Frequency
= 650 Hz
K-factor
(compensated)
= 10.715 (via Field Communicator or AMS)
M = F(Hz) /(K x C
16
)
= 650/{10.715 x (C
11
/
= 650/{10.715 x (0.0733811/4.169
= 650/(10.715 x 0.017602
= 3446.4 kg/hr
I
FHzKC
16
LRV–
URV LRV–
-----------------------------------------------------------
16
4+=
I
275 10.715 0.0176020–
3600 0–
----------------------------------------------------------------------------------
16
4+=