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Reference Manual
00809-0100-4860, Rev BC
Appendix C: Electronics verification
January 2013
Electronics verification
C.3.2 SI units
Example 1 (SI units)
Therefore, an input frequency of 80.00 Hz represents a flow rate of 1694.6 lpm in this
application.
For a given input frequency, you may also determine the current output. Use the above example
with an input frequency of 80.00 Hz:
URV= 2000 lpm LRV= 0 lpm F
in
(Hz) = 80.00
= 17.49 mA
Therefore, an input frequency of 80.00 Hz represents a current output
of 17.49 mA.
Fluid = Water URV = 2000 lpm
Line size = 80 mm. LRV = 0 lpm
Line pressure = 700 kPas C
8
= 4.40287E-03 (from
Table C-1 on
page C-125
)
Operating
Temperature
= 60 °F
Input
Frequency
= 80 Hz
K-factor
(compensated)
= 10.772 (via Field Communicator or AMS)
M = F(Hz) /(K x C
8
)
= 80/(10.722 x 0.00440287)
= 1694.6 lpm
I
FHzKC
8
LRV–
URV LRV–
-------------------------------------------------------------
16
4+=
I
80 10.772 0.004402870–
2000 0–
--------------------------------------------------------------------------------------
16
4+=