Carrier 50XP Air Conditioner User Manual


 
11
50XP UNIT SUGGESTED RIGGING
12
34
A07216
DETAIL A
(914 mm)
A08005
Unit*
SMALLCABINET LARGECABINET
024 024 030 030 036 036
Unit*
042 042 048 048 060 060
lb kg
lb kg lb kg
lb kg lb kg lb kg
Rigging
Weight
345 156 349 158 367 166
Rigging
Weight
425 193 459 208 504 229
NOTE: See dimensional drawingfor corner weightdistribution.Corner weightsshownon drawing are basedon unit ---only weightsand do not includepack-
aging.
SELECTION PROCEDURE (WITH EXAMPLE)
1. Determine cooling and heating requirements at
design conditions:
Given:
Required Cooling Capacity (TC) 34,500 Btuh..........
Sensible Heat Capacity (SHC) 26,000 Btuh............
Required Heating Capacity 15,000 Btuh...............
Condenser Entering Air Temperature 95°F(35°C)........
Indoor--Air Temperature 80°F(26°C) edb.............
67°F(19°C) ewb
Evaporator Air Quantity 1200 CFM..................
External Static Pressure 0.20 IN. W.C..................
Electrical Characteristics 230--1--60...................
2. Select unit based on required cooling capacity.
Enter Net Cooling Capacities table at condenser entering
temperature of 95°F(35°C). The 036 unit at 1225 CFM and 67°F
(19°C) ewb (entering wet bulb) will provide a total capacity of
36,500 Btuh and a SHC of 27,600 Btuh. Calculate SHC correction,
if required, using Note 4 under Cooling Capacities t ables.
3. Select electric heat.
The required heating capacity is 15,000 Btuh.
Determine a dditional electric heat capacity in kW.
15,000 Btuh
= 4.4kW of heat required
3,414 Btuh/kW
Enter the Electric Heater Packages table for 208/240, single--phase,
036 unit. The 5 kW heater at 240v most closely satisfies the
heating required. To calculate kW at the 208v, multiply the heater
kW by multiplication factor 0.75 found in the Wattage
Multiplication Factors table.
5 kW x 0.75 = 3.75 kW
3.75 kW x 3414 = 12,802.50 Btuh
4. Determine fan speed and power requirements at
design conditions.
Before entering the air delivery tables, calculate the total static
pressure required. From the given example, the Filter Pressure
Drop Table, and the Accessory Electric Heat Pressure Drop table,
find:
External Static Pressure 0.200 IN. W.C.
Filter 0.130 IN. W.C.
Wet Coil Pressure Drop 0.032 IN. W
.C.
Total Static Pressure 0.362 IN. W.C.
Enter the table for Dry Coil Air Delivery—At 0.362 IN. W.C. ESP
(external static pressure) and NOM speed pin selection, the motor
will deliver 1235 cfm.
5. Select unit that corresponds to power source
available.
The Electrical Data Table shows that the unit is designed to operate
at 208--1-- 60.
50XP