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Table 2 — Electrical Data
UNIT
50LJQ
NOMINAL
V-PH-HZ
VOLTAGE
RANGE
COMPR
(each)
OFM IFM ELECTRIC HEAT POWER SUPPLY
ELECTRIC HEAT
POWER WIRING
FIG. NO.
ELECTRIC HEAT
PART NO.
50DJ901—
Min Max RLA LRA FLA Hp FLA
Nominal
kW*
FLA MCA MOCP†
008
220-3-50 198 242 15.3 82.0 1.5 1.5 5.8
— — 41.7 50 — —
9.5 24.7 70.3 80 10 711
14.6 38.0 85.7 90 10 601
22.7 59.0 130.0 150 11 611
29.3 76.2 158.5 175 11 621
38.8 100.9 179.5 200 12 711, 621**
400-3-50 360 440 7.7 41.0 1.5 1.5 2.6
10.5 15.2 21.4 25 7 681
12.5 18.0 44.0 45 7 631
21.0 30.3 59.3 60 8 641
25.0 36.1 66.5 70 8 651
31.5 45.5 78.3 80 9 681, 641**
012
220-3-50 198 242 19.6 105.0 1.5 2.0 7.5
— — 53.1 60 — —
9.5 24.7 81.6 90 10 711
14.6 38.0 97.1 100 10 601
29.3 76.2 141.3 150 11 621
43.9 114.1 190.9 200 13 601, 621**
400-3-50 360 440 10.4 55.0 1.5 2.0 3.5
10.5 15.2 28.4 35 7 681
12.5 18.0 51.0 60 7 631
21.0 30.3 66.3 70 8 641
25.0 36.1 73.5 80 8 651
31.5 45.5 85.2 90 9 681, 641**
37.5 54.2 96.6 100 9 631, 651**
LEGEND
COMPR — Compressor
FLA — Full Load Amps
HACR — Heating, Air Conditioning and Refrigeration
IFM — Indoor-Fan Motor
LRA — Locked Rotor Amps
MCA — Minimum Circuit Amps
MOCP — Maximum Overcurrent Protection
OFM — Outdoor-Fan Motor
RLA — Rated Load Amps
*Heaters are field-installed only. Heater capacity (kW) is based on
heater voltage of 230 v or 400 v. If power distribution voltage to unit
varies from rated heater voltage, heater kW will vary
accordingly.
†Fuse or HACR circuit breaker.
**Requires 2 heater packages.
NOTES:
1. MCA and MOCP values are calculated in accordance with NEC
(National Electric Code) (U.S.A. Standard), Article 440.
2. Motor RLAand FLAvalues are established in accordance with UL
(Underwriters’ Laboratories) Standard 465 (U.S.A. Standard).
3. Unbalanced 3-Phase Supply Voltage
Never operate a motor where a phase imbalance in supply volt-
age is greater than 2%.
Use the following formula to determine
the % voltage imbalance.
% Voltage Imbalance
max voltage deviation from average voltage
= 100 x
average voltage
Example: Supply voltage is 400-3-50.
AB = 393 v
BC = 403 v
AC = 396 v
393 + 403 + 396
Average Voltage =
3
1192
= = 397
3
Determine maximum deviation from average voltage.
(AB) 397 − 393=4v
(BC) 403 − 397=6v
(AC) 397 − 396=1v
Maximum deviation is 6 v.
Determine % voltage imbalance.
6
% Voltage Imbalance = 100 x = 1.5%
397
This amount of phase imbalance is satisfactory as it is below the
maximum allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is
more than 2%, contact your local electric utility company
immediately.
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