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At 26˚CDB, 19˚CWB of Indoor,
Q = 21.3, SHC = 16.3, T/I = 8.3
Therefore, when air flow is 77(CMM)
Q = 21.3 ✕ (1+(1.025 - 1.0) ✕ 7/10*) 21.7(kW)
SHC = 16.3 ✕ (1+(1.044 - 1.0) ✕ 7/10*) 16.8(kW)
T/I = 8.3 ✕ (1+(1.009-1.0))✕ 7/10*) 8.4(kW) Note * : 7/10 = (77-70)/(80-70)
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(Step-3) Calculation of net capacity
Based on the indoor conditioned temperature (WB,DB), designed outdoor temperature (DB), and the
actual air flow obtained in Step-2, obtain the gross capacity from the gross capacity tables (pages
16~35). Then, calculate the net capacity from the formula below by using the fan motor input obtained
in Step-2.
Net capacity (kW) = Gross capacity (kW) - Fan motor input (kW)
Example: PE-8MYC
Condition:
Indoor conditioned temp. : 26˚CDB, 19˚CWB
Designed outdoor temp. : 40˚CDB
Actual air flow : 77CMM
Fan motor input : 0.6kW (See P.11)
Calculation :
The sections of the gross capacity table applicable
for the above conditions are shown right.
Therfore, the net capacity is,
Net total cooling capacity = 21.7 (kw) - 0.6(kW)
= 21.1 (kW)
Net sensible cooling capacity = 16.8 (kW) - 0.6 (kW)
= 16.2 (kW)
• Refrigerant cycle energy efficienty
(1) COP =
(2) ERR =
• System energy efficienty
(1) COP =
(2) ERR =
Notes: 1. COP : Coefficient of performance
2. EER : Energy efficiency ratio
3. Temperature condition of COP, EER (ARI Standard Ratings)
Indoor entering air temp. : 80˚FDB (=27˚CDB), 66˚FWB(=19˚CWB)
Outdoor entering air temp. : 95˚FDB (=35˚CDB)
4. Total input = Compressor input + Indoor fan motor input + Outdoor fan motor input (page 11).
Gross total cooling capacity (kW)
Compressor input (kW)
Gross total cooling capacity (kW)
Total input (kW)
Net cooling capacity (kW)
Compressor input (kW)
Net cooling capacity (kW)
Total input (kW)
PE-8MYC-EU
AIR VOLUME
CMM 60 70 80
L/S 1,000 1,167 1,330
COOLING
CAPACITY 0.976 1.0 1.025
SHC 0.963 1.0 1.044
TOTAL INPUT 0.991 1.0 1.009
21.3 16.3 0.77 8.3
OUTDOOR DB˚C
INDOOR INDOOR
40.0
Q kW
SHC kW
SHF T/I kW
DB˚C
WB˚C
26 19
Factor for Various Air Flow
1kW = 3412Btu/h
2. Efficiency Calculation