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Table 2 – Electrical Data, Alternate Motors
UNIT V --- PH --- Hz
{
VOLTAGE
LIMITS
FAN MOTOR POWER SUPPLY
Hp (kW) FLA
Minimum
Circuit Amps
MOCP
524J*16A
524J
*16H
208/230---3---60 187---253 5.0 (3.73) 14.6/12.8 18.3/16.0 30/25
460 --- 3 --- 60 414---506 5.0 (3.73) 6.4 8.0 15
575 --- 3 --- 60 518---632 5.0 (3.73) 5.1 6.4 15
524J*25A
524J*25H
208/230---3---60 187---253 7.5 (5.59) 21.4/19.4 26.9/24.3 45/40
460 --- 3 --- 60 414---506 7.5 (5.59) 9.7 12.1 20
575 --- 3 --- 60 518---632 7.5 (5.59) 7.8 9.8 15
524J*28A
524J*30A
208/230---3---60 187---253 10.0 (7.46) 28.2/26.8 35.3/33.5 60/60
460 --- 3 --- 60 414---506 10.0 (7.46) 13.4 16.8 30
575 --- 3 --- 60 518---632 10.0 (7.46) 10.3 12.9 20
NOTE: See below for table legend and notes
Legend and Notes for Tables 1 and 2
LEGEND:
FLA --- Full Load Amp s
MOCP --- Maximum Overcurrent Protection
{
Motors are designed for satisfactory operation within 10% of
normal voltage shown. Voltages should not exceed the limits
shown in the Voltage Limits column.
NOTES:
1. Minimum circuit amps (MCA) and MOCP values are calcu-
lated in accordance with The NEC. Article 440.
2. Motor FLA values are established in accordance with Under-
writers’ Laboratories (UL). Standard 1995.
3. Unbalanced 3- Phase Supply Voltage
Never operate a motor where a phase imbalance in supply
voltage is greater than 2%. Use the formula in the example
(see column to the right) to determine the percentage of volt-
age imbalance.
4. Installation with Accessory Electric Heaters
Size the Field Power Wiring between the heater TB1 and the
40RU indoor fan motor per NEC Article 430---28 (1) or (2)
(depends on length of conduit between heater enclosure and
40RU power entry location). Ins tall wires in field---installed
conduit.
Example: S upply voltage is 230-3-60
% Voltage Imbalance =100 x
max voltagede viation from average voltage
averagevoltage
AB = 393 v
BC = 403 v
AC = 396 v
Average Voltage =
(393 + 403 + 396)
=
1192
3
3
= 397
Determine maximum deviation from average voltage.
(AB) 397 – 393 = 4 v
(BC) 403 – 397 = 6 v
(AC) 397 – 396 = 1 v
Maximum deviation is 4 v.
Determine percent of voltage imbalance.
% Voltage Imbalance = 100 x
6
397
=1.5%
This amount of phase imbalance is satisfactory as it is below the
maximum allowabl e 2%.
IMPORTANT: If the supply voltage phase imbalance is more than
2%, contact yo ur local electric utility company immediat ely.
2011 Bryant Heating and Cooling Systems. D 7310 W. MorrisSt. D Indianapolis,IN 46231 Printed in U.S.A. Edition Date: 01/11
Manufacturer reserves the right to change, at any time, specifications anddesigns without notice andwithout obligations.
Catalog No: SS524J---01
Replaces:New
524J